一条例子:
select count(point_id) as today_sum from point where datediff(d,point_date,getdate())=0
关键语句:
datediff(d,point_date,getdate())=0
select count(point_id) as today_sum from point where datediff(d,point_date,getdate())=0
关键语句:
datediff(d,point_date,getdate())=0